Let g(x) = 4x+1, 25 x SX, 0 < x < 2 If y is a solution for y' - y = g(x), y(0) = 0, then L(y) = 1+se-s (a) s(s+2) 1+se -

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Let G X 4x 1 25 X Sx 0 X 2 If Y Is A Solution For Y Y G X Y 0 0 Then L Y 1 Se S A S S 2 1 Se 1 (103.77 KiB) Viewed 77 times

Let g(x) = 4x+1, 25 x SX, 0 < x < 2 If y is a solution for y' - y = g(x), y(0) = 0, then L(y) = 1+se-s (a) s(s+2) 1+se -25 (b) s2 (+1) 1+se-s (c) s2 (3-2) 1+se-2 (d) S2(S-1) (e) 1+ses S2 (s+1)