Given the single line diagram of a 3-phase system below showing two networks (A & B) interconnected by a three-phase tra

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Given The Single Line Diagram Of A 3 Phase System Below Showing Two Networks A B Interconnected By A Three Phase Tra 1 (152.93 KiB) Viewed 24 times

Given the single line diagram of a 3-phase system below showing two networks (A & B) interconnected by a three-phase transmission line TL AB. The line is protected by it's corresponding distance relays (ANSI device number 21) at both end sub-stations and power circuit breakers PCB-A & PCB-B. Before the occurrence of a solid three-phase line-to-ground fault (zero fault impedance - hence zero voltage at point C), the normal current IAn (and power flow) is from Bus A to Bus B. Obviously, during the fault, the fault currents IAf and IBf are both rushing towards the fault at point C. FAULT AT POINTC BUS B BUS A Fault Current Af→ Fault Current IBfE Net- work A Net- work B PCB-A Transmission Line PCB-B 300 38 21 € Distance Relay A Distance Relay B 11 at sub-station A transmission line at sub-station B VBnm = 37.23672341 (magnitude of VAnm = ??? (magnitude of line-to ground voltage in kV under normal Trpkm = 0.08 (resistance line-to-ground voltage in kV under or pre-fault condition at Bus A) per phase in Ohms per km) normal or pre-fault condition at Bus B) Tlxpkm = 0.52 (inductive VBna = VAna = ??? (angle in degrees of VAN) -6.376927231 (angle in reactance per phase in Ohms per km) degrees of Ven) IAnm 0.44 (magnitude of IBnm (magnitude of TLkm = 37 (transmission transmission line current in kA under transmission line current in KA line length per phase in normal or pre-fault condition at Bus under normal or km) pre-fault A) condition at Bus B) Ana = -3 (angle in degrees of An) IBna = (angle in degrees of IBn) VAfm = 23.25 (magnitude of line to VBfm = 33.51305107 (magnitude of ground voltage in kV under faulted line-to-ground voltage in kV under condition at Bus A) faulted condition at Bus B) IAfm = 5.971840429 (magnitude of IBfm = 2.149298251 (magnitude of transmission line current in KA under transmission line current in KA under faulted condition at Bus A) faulted condition at Bus B) ACkm = ??? distance from bus A to BCkm = ??? distance from bus B to fault point C in km fault point C in km NOTE: If values are blank (or ???) in the table above, it means they are not given and you may (or do not) have to solve for them. You may round-off the given down to four decimal places if you wish.