Experiment Number: M4 Experiment Name: Spring Pendulum Assignment: To find out the factors affecting the period of oscil

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Experiment Number: M4 Experiment Name: Spring Pendulum Assignment: To find out the factors affecting the period of oscil

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Experiment Number M4 Experiment Name Spring Pendulum Assignment To Find Out The Factors Affecting The Period Of Oscil 1
Experiment Number M4 Experiment Name Spring Pendulum Assignment To Find Out The Factors Affecting The Period Of Oscil 1 (108.36 KiB) Viewed 59 times
Experiment Number: M4 Experiment Name: Spring Pendulum Assignment: To find out the factors affecting the period of oscillation 'T' of a spring pendulum and also determine the spring constant. Tabel-1: Period of oscillation ‘T' as a function of deflection. (m=150gm) Time taken for 10 Deflection L oscillations Period of oscillation (cm) 10T (sec) 1 11.38 2 11.40 T (sec) Table-2: Period of oscillation 'T' as a function of mass. (suitable deflection) Mass m Time taken for 10 Period of oscillations oscillation (gm) Tº (sec) 10T (sec) T (sec) 100 9.70 150 11.38 200 13.42 250 14.71 300 16.25 Tabel-3: Period of oscillation ‘T'as a function of spring diameter (m=150gm; Deflection = 2cm) Spring Time taken for 10 Period of Diameter oscillations oscillation D (cm) 10T (sec) T(sec) 2.0 7.50 11.38 3.0 Comment on the given data to know about the factors affecting the period of oscillation. Draw graph: T2 vs m

Result: The values of spring constants are: From collected data: From graph: Answer the following Questions: Q2. Why the values of spring constants are different for different sets of data of a spring? Q3. How you can get the value of spring constant, K from the graph?

out a A nature and is physical а Experiment no : M4 bolalawi Experiment names Spring Pendulum. Partyinend alipeline to one and the Belous alleching de the Priced of estilkelion Tof a thing berbulum and also determine the string constant Theory: A string bendulum (also called elastic prodhul.com mestnything thing ) a Hyred obydon show a Pace system where prece of mass is connected to spring so that the moscalling motion contains elements of a simple fendulum as spring. When a string trung is stretched on compressed, the force required to streche the sering is often by Hocke's Law: F = – kx x 45 distance the abreng is stretched on compressed and K is the constant determines the "stiffn # 83 mess of the thing Newton/meter. The ménin sem tendicates the force Points in the direction obpaste to the replacement. as well tring 火 Where f. is the force, constant. The string strong and is measured in Foi

- en a String wing Newton's and leads to a The normal method of the motion of a mass analyzing differential equation, which will the time period of oscillation. However, we can state the result for the period of mass on a skring 1 as: mm T= 200k where k is olarne k the string ons land for the thing 1. the oscillationg mans end my the mass attached to the thing at the end and m Bis is Diagram K 9 1 Esp Uncinetched x string The block hanging at rest w m This is the blockt esulibrium Pisition the point with no olant net fonce,

Apparatus? 1. Saung Pendulum 2. Stop watch 3. Mass (50.100, 150,200,250 and 300 gm Observations and Measurements: Table - 1 Period of oscillation 'T' as a function of det letion. (M = 150 gm Deflection 2. The taken fue to Average time taken Pariod of Time for (cm) | fort 10 oscillation oscillation 10 T (sec) 107 €) T (Soc) 1 1. 10.88 Hi- 10.47 1.07 10.675 bola baie 9. 11.00 2 10.965 1.09 13. 10.93 w of 19. 11.06 3 10.86 1.08 1.1.66 Table - 2: Period of astillation 'T'as a function of mass. (Deflection (Deflection = 2cm)

Mass m (47) 100 Time taken for 10 Avertage time Petrodo Pernod of T'exce") Th ( oscillations Halen en 10 osallation 10 Tue) Ofila ons Thec) 10T (4) 1.00 8.94 1.8.88 + 1. 11.00 10.995 1.099 1. 208 11. 10.99 0.894 0.799 150 12.595011259 1.585 200 12.47 1.12.42 250: 9-13.91 A 13.845 1.384 1.915 *. 13.7831 . 300 1.15. 16) 102 15.11 1.511 2.289 fi. 15.06 a function Table - 3: Period of oscillation 'T' as 3 of string diameter (me - 150 gms = Deflection den Time taken Average time Spring Diametent for 10 osallations taken for 10 - Pensiod of oscillation Tfxe) D(em) Oscillations 10 T (de) 10 T (AC) 9. 7.34 1.7.56 2 7.45 0.745 3 10.9C5 1.096 1. 10.99

Calculation & 4120-150 4 0.200 kg = 40 m, 0.100 4.94 N/m T' 0.99 kg - 472 mi 4.90 Nm T, 1. 208 K3 = 472 mg 4.98 Nym T3 1.585 hoon Ky = 47 ma = 5.15 N/m 1.915 kg = 402 mg ! 15 2.28 KA 4.94 +4.50 +4.98+5.15+5.19 5 4020:25 0 14 = 4' 0.300 = 5.1 N/m 5.032 N/m 2cm diameter and mass KB = 402 X- 150 gm ono:15 kg (0.7452 0.15 = 10 669 N/m

Result analysis We get sering con constant KA = 5.032 N/m from table + 02 and ko 10.669 N/m from table -03. These are theoretical vakres. birst from , graph-2, we can see the equation of trendline y = 0.0073x + 0.0898 there, slope is un m 0.0073 scelem • 7.3 sec jug 4 y- kgraph 4 x 1/43 LL slope m 7,3 5.408 N/m

- 10 et The differenes -(kgraph – ka) as ponta a - (5.408 – 5.052) 0.376 N/m Se there is a difference between theori tical voks and graphical value of Arling constant. [ graphical image. "kB has no И . ant binar [ 28 semanney experimental -expected value HX100% expected value interes 5.408 - 5.032 PX100% 2 beri bilan 5.032 7.47% wallos 2
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