1. You are studying a myelinated axon with the following values. P=0.95, Kn=200mm Kout=5mM, PNa=0.05, Nan=5mM, Naout=130

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1. You are studying a myelinated axon with the following values. P=0.95, Kn=200mm Kout=5mM, PNa=0.05, Nan=5mM, Naout=130

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1 You Are Studying A Myelinated Axon With The Following Values P 0 95 Kn 200mm Kout 5mm Pna 0 05 Nan 5mm Naout 130 1
1 You Are Studying A Myelinated Axon With The Following Values P 0 95 Kn 200mm Kout 5mm Pna 0 05 Nan 5mm Naout 130 1 (38.93 KiB) Viewed 55 times
1. You are studying a myelinated axon with the following values. P=0.95, Kn=200mm Kout=5mM, PNa=0.05, Nan=5mM, Naout=130mm. a) The Na+ channels in a node of Ranvier open causing a 30 ns increase in conductance. What is the total current? (hint: I = 9 (V-Ena), Sis the unit for conductance (9).) b) What is the depolarization caused by this current, if the Rm=8 M2? c) What will be the depolarization at the next node if the Rm along the internode is 1MD2*cm and the Ri is 10M22 cm, and the internode is 0.1cm long? [hint: Vx = Voemh, 2 = VRm/R) d) What parameter changes in a demyelinating disease? Why? What will happen to action potential propagation?
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