0 = 10 (radians/s] R = 0.05 [m] R = 0.06 [m] oil Drum H = 0.15 [m] Can Side View Top View The above figure shows the top

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0 10 Radians S R 0 05 M R 0 06 M Oil Drum H 0 15 M Can Side View Top View The Above Figure Shows The Top 1 (183.25 KiB) Viewed 38 times

0 = 10 (radians/s] R = 0.05 [m] R = 0.06 [m] oil Drum H = 0.15 [m] Can Side View Top View The above figure shows the top and side views of a cylindrical drum of radius Rị = 0.05[m] and hei H = 0.15[m] that is spinning at w = 10[radians/s]. The drum is inside an open cylindrical can of radius R.= 0.06[m]. The can is stationary and is concentric with the drum. The drum is surrounded by SAE 10W30 oil at 30[°C] (or 303[K]). In the gap between the side of the drum and the side of the can, the tangential velocity of the oil is given by: Vic R. ve(r) = (B2 – 1)lr (rGohana for Ri <r <R. R. = where ß = R,/Ri, Vi is the oil velocity at the side wall of the drum, and r is the radial distance from the axis of rotation. a) Estimate Vi, the speed of the oil at the side wall of the drum. b) Determine the numerical value of the constant, C. c) Estimate the torque required to spin the drum at w = 10[radians/s]. You may neglect the effect of the oil on the top and bottom surfaces of the drum.