4, In the two-dimensional flow field in the UT right figure, an incompressible and constant- property fluid flows parall

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

4, In the two-dimensional flow field in the UT right figure, an incompressible and constant- property fluid flows parall

Post by answerhappygod »

4 In The Two Dimensional Flow Field In The Ut Right Figure An Incompressible And Constant Property Fluid Flows Parall 1
4 In The Two Dimensional Flow Field In The Ut Right Figure An Incompressible And Constant Property Fluid Flows Parall 1 (67.91 KiB) Viewed 15 times
4, In the two-dimensional flow field in the UT right figure, an incompressible and constant- property fluid flows parallel to an inclined surface. The heat flux at surface varies according to 95(x) = 450e-ax At any location along the surface, a fraction y of the heat flux is absorbed at the surface, and the remainder causes volumetric energy deposition in the fluid according to 90(x,y) = 95(x)(1 - y)be-bx a) Write the momentum and energy conservation equations, and their boundary conditions, for the flow field. Note that the equations should not include redundant terms. b) Do velocity and temperature boundary layers form on this surface? If they do, assume that the fluid has the properties of water at 300 K and U. = 2.0 m/s, and calculate the thickness of the boundary layers at a location where Rex = 1.25 x 105. c) Assume that the velocity profile near the surface approximately follows: y Sie) - (*ir si U. > Derive an expression which can be used to compare the volumetric energy deposition rate with volume viscous dissipation rate. d) Assume that the fluid has the properties of water at 300 K and U. = 2.0 m/s. For the location where Rex = 1.25 x 105 and assuming that the velocity profile near the surface approximately follows the preceding expression, calculate the volumetric viscous dissipation rate at a distance off = 1/2 from the wall. u 1-0-10v1
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply