Consider the dissociation of CO2 given by 𝐶𝑂2 ⟷ 𝐶𝑂 + 0.5𝑂2 As a function of temp

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Consider the dissociation of CO2 given by
𝐶𝑂2 ⟷ 𝐶𝑂 + 0.5𝑂2
As a function of temperature and pressure. Find the equilibrium
composition of the mixture, i.e. the mole fractions of CO2, CO, and
O2 that results from subjecting the originally pure CO2 to
temperatures of T = 1500, 2000, 2500, and 3000 K and pressures of p
= 0.1, 1, 10 and 100 atm, respectively. Synthesize your results and
show that they agree with La Chatelier’s Principle, i.e.
i) at fixed temperature, as pressure increases dissociation is
suppressed, while
ii) at fixed pressure, as temperature is increased, dissociation
is promoted.

Consider The Dissociation Of Co2 Given By Co2 Co 0 5o2 As A Function Of Temperature And Pressure Find The Equilibri 1 (70.08 KiB) Viewed 43 times

Ans. p (atm) 0.1 1 10 100 . XCO2 1 T(K) 1500 2000 2500 3000 0.999 0.953 0.661 0.244 0.999 0.978 0.819 0.463 0.99 0.91 0.678 1 0.995 0.957 0.829 p (atm) 0.1 1 10 100 XCO T(K) 1500 2000 2500 3000 7.75E-04 3.60E-04 1.67E-04 7.76E-05 3.14E-02 1.48E-02 6.93E-03 3.23E-03 2.26E-01 1.21E-01 6.02E-02 2.89E-02 5.04E-01 3.58E-01 2.14E-01 1.14E-01 p (atm) 0.1 1 10 100 XO2 T(K) 1500 2000 2500 3000 3.88E-04 1.80E-04 8.35E-05 3.88E-05 1.57E-02 7.41E-03 3.47E-03 1.62E-03 1.13E-01 6.05E-02 3.01E-02 1.47E-02 2.52E-01 1.79E-01 1.07E-01 5.69E-02