From the following enthalpies of reaction: H2(g) +F2(g) 2HF(8), AH = -537 kJ C(s) + 2F2 (g) CF4(6), ΔΗ -680 kJ 2C(s) + 2

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From the following enthalpies of reaction: H2(g) +F2(g) 2HF(8), AH = -537 kJ C(s) + 2F2 (g) CF4(6), ΔΗ -680 kJ 2C(s) + 2H2(g) → CH(6). +52.3 kJ calculate AH for the reaction of ethylene with Fa: CH_() +6F () - 2CF: (x) + 4HF(x) Express your answer in kllojoules to three significant figures. AH = Templates Symbols undo relo reset keyboard shortcuts Help ΔΗατι -2486.3 kJ 3 Submit Previous Answers Request Answer X Incorrect; Try Again Before summing the AH values of each of the stope, manipulate the reactions with the given enthalpies so that the reactants and products of the overall action appear on the appropriate sides of each equation Recall that, when the direction of a reaction is reversed the sign of the enthalpy change is also reversed First launch this video. During the video, you'll see an example of a simiar problem. After watching the video, by the question again. You can watch the video again at any point