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2 points В 750 с 200 kg if the shown weight is suspended using two cables (AC & BC). The tension in cable AC to maintain the equilibrium at equals (9 = 9.81 m/s2) O A 1590 N OB. 1086 N
-15 in Н 65 TL 60 lb The force of 60 lb at A is connected to the shown weight of 65 lb through a frictionless pulley at
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-15 in Н 65 TL 60 lb The force of 60 lb at A is connected to the shown weight of 65 lb through a frictionless pulley at
-15 in Н 65 TL 60 lb The force of 60 lb at A is connected to the shown weight of 65 lb through a frictionless pulley at B. The horizontal force should be applied at A to maintain the system in equilibrium equals a OA 35 lb
2 points В 750 с 200 kg if the shown weight is suspended using two cables (AC & BC). The tension in cable AC to maintain the equilibrium at equals (9 = 9.81 m/s2) O A 1590 N OB. 1086 N
2 points В 750 с 200 kg if the shown weight is suspended using two cables (AC & BC). The tension in cable AC to maintain the equilibrium at equals (9 = 9.81 m/s2) O A 1590 N OB. 1086 N