*2.4.1. Solve the heat equation du/at = każu/ax?, 0<x<L, t > 0, subject to ди (0,t) = 0 ac t> 0 du thooo (L, t) = 0 ax t> 0. (a) u(x,0) = { 3770 (b) u(x,0) = 6 + 4 cos L so x <L/2 1 x > L/2 8πα (d) u(x,0) = -3 cos L πα L (c) u(x,0) = -2 sin
*2.4.1. Solve the heat equation du/at = każu/ax?, 0 0, subject to ди (0,t) = 0 ac t> 0 du thooo (L, t) = 0 ax t
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*2.4.1. Solve the heat equation du/at = każu/ax?, 0 0, subject to ди (0,t) = 0 ac t> 0 du thooo (L, t) = 0 ax t
HELP WITH A, B, C AND D PLS! WILL UPVOTE 
*2.4.1. Solve the heat equation du/at = każu/ax?, 0<x<L, t > 0, subject to ди (0,t) = 0 ac t> 0 du thooo (L, t) = 0 ax t> 0. (a) u(x,0) = { 3770 (b) u(x,0) = 6 + 4 cos L so x <L/2 1 x > L/2 8πα (d) u(x,0) = -3 cos L πα L (c) u(x,0) = -2 sin
*2.4.1. Solve the heat equation du/at = każu/ax?, 0<x<L, t > 0, subject to ди (0,t) = 0 ac t> 0 du thooo (L, t) = 0 ax t> 0. (a) u(x,0) = { 3770 (b) u(x,0) = 6 + 4 cos L so x <L/2 1 x > L/2 8πα (d) u(x,0) = -3 cos L πα L (c) u(x,0) = -2 sin
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