What temperature is required to obtain 0.60% C at a distance of 0.5 mm beneath the surface of a 0.18% C steel in 2 hours
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What temperature is required to obtain 0.60% C at a distance of 0.5 mm beneath the surface of a 0.18% C steel in 2 hours
What temperature is required to obtain 0.60% C at a distance of 0.5 mm beneath the surface of a 0.18% C steel in 2 hours, when 1.2% C is present at the surface? Given: Cx Со х * = 1 -erf = Cs Со 2Dt where: D = Doexp(-RE Q RT Where: R = 8.31 J/mol.K Do = 0.00005 m/s Q = 284 kJ/mol
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