y' = sin(y) + 10 exp(-5(x - 1)?),0 < x <2, y(0) = 1. = 0 AP 1 4 9 1 4 3 8 12 13 ~~ I 32 7200 2197 1 1 32 1932 2197 4

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answerhappygod
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y' = sin(y) + 10 exp(-5(x - 1)?),0 < x <2, y(0) = 1. = 0 AP 1 4 9 1 4 3 8 12 13 ~~ I 32 7200 2197 1 1 32 1932 2197 4

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Y Sin Y 10 Exp 5 X 1 0 X 2 Y 0 1 0 Ap 1 4 9 1 4 3 8 12 13 I 32 7200 2197 1 1 32 1932 2197 4 1
Y Sin Y 10 Exp 5 X 1 0 X 2 Y 0 1 0 Ap 1 4 9 1 4 3 8 12 13 I 32 7200 2197 1 1 32 1932 2197 4 1 (1.44 KiB) Viewed 67 times
Y Sin Y 10 Exp 5 X 1 0 X 2 Y 0 1 0 Ap 1 4 9 1 4 3 8 12 13 I 32 7200 2197 1 1 32 1932 2197 4 2
Y Sin Y 10 Exp 5 X 1 0 X 2 Y 0 1 0 Ap 1 4 9 1 4 3 8 12 13 I 32 7200 2197 1 1 32 1932 2197 4 2 (134 Bytes) Viewed 67 times
Comparing the result with the Runge-Kutta 4th order method.
What is the approximation value for y(2)?
What step size is used in the last approximation step?
What is the maximum and minimum step size used?
How often does it happen in our example that a step size is not accepted?
y' = sin(y) + 10 exp(-5(x - 1)?),0 < x <2, y(0) = 1. =

0 AP 1 4 9 1 4 3 8 12 13 ~~ I 32 7200 2197 1 1 32 1932 2197 439 216 25 216 -8 7296 2197 3680 513 1408 2565 845 4104 2197 4104 1 0 -! |
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