The logic of the following pseudocode is flawed. declare a Stack of characters balanced True while more input is availab

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The Logic Of The Following Pseudocode Is Flawed Declare A Stack Of Characters Balanced True While More Input Is Availab 1 (38.91 KiB) Viewed 31 times

The logic of the following pseudocode is flawed. declare a Stack of characters balanced True while more input is available: read a character if character is a 'c': push it onto Stack elif character is a ") and Stack is not empty! pop a character from Stack else: balanced = False if balanced: print "balanced" else: print "unbalanced" According to this pseudocode, which of the following inputs will be flagged incorrectly as being balanced"? O a (0) Cross out Cross out O b. (0) Oc (0) O d. (00)) CROSS Out CROSS Out