2. The pendulum consists of a slender rod with mass/length of 3 kg/m joined to a thin plate with mass/area of 12 kg/m2 w

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2. The pendulum consists of a slender rod with mass/length of 3 kg/m joined to a thin plate with mass/area of 12 kg/m2 w

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2 The Pendulum Consists Of A Slender Rod With Mass Length Of 3 Kg M Joined To A Thin Plate With Mass Area Of 12 Kg M2 W 1
2 The Pendulum Consists Of A Slender Rod With Mass Length Of 3 Kg M Joined To A Thin Plate With Mass Area Of 12 Kg M2 W 1 (684.97 KiB) Viewed 49 times
2. The pendulum consists of a slender rod with mass/length of 3 kg/m joined to a thin plate with mass/area of 12 kg/m2 which contains a circular hole. a) Use the table method to determine the y-bar position of the systems Center of Mass with respect to the pivot point 'O'. b) Calculate the Mass Moment of Inertial IGxx of the pendulum about x axis running thru the systems C-of-M (i.e. parallel to the pivot). c) Finally calculate the radius of gyration, ksys of the pendulum with respect to the x axis. Note: All dimensions in meters 1.5 х Ć 0.4 See back for table formats. Dia 0.35 0.2 1 0.4 0.4

Center of Gravity Calculation: Object Mass yrbar (m) (kg) (m)(y-bar) Multiplieri (kg m) ( ) Ref Multiplier 1 (real) ) 2 (real) ) 3 (void) ) Σ= ( > ( )! Σ= and y-bar = (m)(y-bars) / Em = Note: Primitives identified as Voids' have (-1) multipliers prior to summation. Mass Moment of Inertia Calculations for systems composed of multiple primitives: Mass Igor about dshin from x axis Object Ref (Type) 1 (real) 2 (real) primitive CoM Eqn (kg.m2) (kg) md? LGxx = ( ( 1gxx + md?] Term contribution towards total (kg.m?) Multiplier (kg.m3) ) ( ( DI IGxx = = 3 (void) Note: Primitives identified as 'Voids' have (-1) multipliers prior to summation. Note: To receive a passing grade, 80% of all assigned work must be attempted. 2
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