Expert Q&A Done 1. A researcher titrates a 100 ml solution of 0.1 M glycine at pH 1.72 with 2 M NaOH solution. She then

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Expert Q A Done 1 A Researcher Titrates A 100 Ml Solution Of 0 1 M Glycine At Ph 1 72 With 2 M Naoh Solution She Then 1 (30.4 KiB) Viewed 72 times

Expert Q&A Done 1. A researcher titrates a 100 ml solution of 0.1 M glycine at pH 1.72 with 2 M NaOH solution. She then monitors the pH and plots the results in the graph shown here. The key points in the titration we designated I through v. 12 LU.JQ (V) 109.60 8 pH 65.97 F 4 2.34 2 GIO OS 20 1.0 15 OH equivalents) For each of the statements, identify the appropriate key point in the titration . The pH is equal to the pKa of the carboxyl group The pH is oqual to the pKa of the amino group The predominant glycine species is +H3N-CH2-COOH d. The predominant glycine species is +H3N-CH2-C00 e. Glycine predominantly exists as a 50:50 mixture of +H3N-CH2-COOH and +H3N-CH2-000- f. The average net charge of glycine is +1. & Half of the amino groups are ionized. . The average net charge of glycine is 0. h. The average net charge of glycine is 0. i. The average net charge of glycine is -1. This is the isoelectric point for glycine. k Glycine has its maximum buffering capacity at these points,