- Please Show Work 1 (109.31 KiB) Viewed 16 times
Please show work.
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answerhappygod
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Please show work.
Please show work.
P III. Heat Pumps 1. For any closed system that operates in a cyclic process we have learned that the change in internal energy of the gas will be zero, (AU = 0). Thus, if we apply the first law of thermodynamics AU = Q - W we can determine that the net amount of work done on the gas will remove heat Q from the gas. This input of mechanical energy will allow heat to be V removed from "colder" objects and rejected to "warmer" objects. Show the direction of the energy flow on the diagram below indicating the values QH, Qc and W for a typical heat pump. List the equation used to relate these three energies as well as the equation for the thermal COP of a heat pump. Hot Reservoir Work = QH - QC THI * QH w O ť Qc Goal QH Qu 31 Thermal COP = - r To Input w QH - Qc Cold Reservoir Question: Explain why the equation for the thermal COP of the heat pump differs from that of the refrigerator and air-conditioner devices. Question: Where does the heat pump actually extract the heat Qc in its operation? Question: How do you rewrite the equation for the COP of the heat pump if it operates on the Carnot cycle? Carnot cop= TH-Tc
P III. Heat Pumps 1. For any closed system that operates in a cyclic process we have learned that the change in internal energy of the gas will be zero, (AU = 0). Thus, if we apply the first law of thermodynamics AU = Q - W we can determine that the net amount of work done on the gas will remove heat Q from the gas. This input of mechanical energy will allow heat to be V removed from "colder" objects and rejected to "warmer" objects. Show the direction of the energy flow on the diagram below indicating the values QH, Qc and W for a typical heat pump. List the equation used to relate these three energies as well as the equation for the thermal COP of a heat pump. Hot Reservoir Work = QH - QC THI * QH w O ť Qc Goal QH Qu 31 Thermal COP = - r To Input w QH - Qc Cold Reservoir Question: Explain why the equation for the thermal COP of the heat pump differs from that of the refrigerator and air-conditioner devices. Question: Where does the heat pump actually extract the heat Qc in its operation? Question: How do you rewrite the equation for the COP of the heat pump if it operates on the Carnot cycle? Carnot cop= TH-Tc