LESSON 2 COMPUTING THE PROBABILITIES AND PERCENTILES OF A NORMAL DISTRIBUTION A. Computes probabilities and percentiles

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Lesson 2 Computing The Probabilities And Percentiles Of A Normal Distribution A Computes Probabilities And Percentiles 1 (76.15 KiB) Viewed 89 times

LESSON 2 COMPUTING THE PROBABILITIES AND PERCENTILES OF A NORMAL DISTRIBUTION A. Computes probabilities and percentiles using the standard normal table. (M11/12SP- lllc-d-1) OBJECTIVES a.) illustrate the Z-score in computing the probabilities; and b.) computes probabilities and percentiles using the standard normal table. B. DISCUSSION Table of z gives: -3.49 to 3.49. Z-score or Standard score tells us how many standard deviations a value is away from the mean. +z-score = above the mean - Z-score = below the mean AREA BELOW (Please refer in the 2-table) 1. Find the area to the left of z = 2.06. 2. Find the area to the left of z = .1.17 Answer: 98.03% Answer: 12.30% AREA ABOVE (Please refer in the z-table) 1. Find the area to the right of 2 = -1.19. 2. Find the area to the right of z= 2.36. Answer:88.30% Answer: 0.91% AREA BETWEEN 1. Find the area between z=1.68 and z=1.37. Solution: @z= 1.68 (below) @z= 1.37 (below) Answer: 95.35% Answer: 91.47% Area between z=1.68 and z=1.37 means area below 2.68 minus area below 1.37 Learning Module in Statistics and Probability Which means 95.35% - 91.47% = 3.88% (the area between z=1.68 and z=1.37) C. ACTIVITY 1. Find the area to the left of 1. z = 2.00 Answer: 2. z = 3.1 Answer: 3. z=-1.5 Answer: 4. Z=2.14 Answer: 5. z=-2.8 Answer: D. ACTIVITY 2. Find the area to the right of 1. z = 3 Answer: 2. z= -2.5 Answer: 3. z=1.25 Answer: 4. Z=-0.15 Answer: 5. Z=3.13 Answer: E. ACTIVITY 3. Find the area between z=2.28 and Z=-1.23