A common source amplifier uses a 4 resistor bias network: 100 kOhm

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A Common Source Amplifier Uses A 4 Resistor Bias Network 100 Kohm Ri 500 Kohm Connected To Vdd 500 Kohm R2 1 Mohm 1 (241.93 KiB) Viewed 74 times

A common source amplifier uses a 4 resistor bias network: 100 kOhm<RI<500 kOhm (connected to VDD), 500 kOhm<R2< 1 MOhm (connected to the Gate), 250 kOhm-RD<500 kOhm (connected to VDD) and 500 kOhm RS<IMOhm (connected to the Source) are the bias resistor and 12 V<V0o<20 V supply voltage values. Choose your own values between these boundaries using interval values (for example you cannot choose 100 kOhm and 500 kOhm for RI) and calculate the Q-point and the transconductance of the transistor, take K-100 mA/V2. Clearly show your selected values. [10] In the amplifier, bypass and DC block capacitors are used that are all at 10 pF. The transistor has 100 kOhm<r <500 kOhm, 2 pF<C,<10 pF and 0.5pF<C 2.5 pF. Choose your own values within these boundaries using interval values (as explained above). The amplifier is fed from a voltage source with an internal resistance of 10 kOhm and is connected to a 200 kOhm load. Draw the equivalent high frequency circuit of the amplifier described above calculate the upper 3-dB frequency f. [15] The engineer wants to double fit , propose two alternatives. Compare these alternatives numerically by calculating their effects and explain the advantages/disadvantages of your proposed solutions. [10]