A Magnetic Circuit Is Given In The Following Figure Where H 00 In Area Aci O G O N Area Ac2 G 30cm2 Cross Section 1 (98.92 KiB) Viewed 34 times
A magnetic circuit is given in the following figure, where H = 00 in Area: Aci O g o N Area: Ac2 g 30cm2 • Cross-sectional area for air gap 1 is Aci = 20cm², for air gap 2 is Ac2 • The air gap length g=0.5cm • The number of turns of the winding N = 200 When the winding current i1 = 1A, please calculate the flux density values in the two air gaps. (Bg1 is for air gap 1 and Bg2 is for air gap 2) O a. Bg1 = 0.025 (T) Bg2 = 0.025 (T) O b. Bg1 = 0.025 (1) Bg2 = 0.10 (T) O c. Bg1 = 0.05 (T) Bg2 = 0.025 (T) O d. Bg1 = 0.10 (T) O e. Bg1 = 0.05 (T) Bg2 = 0.05 (T) Bg2 = 0.05 (T) Of. None of the rest
Now a magnet is inserted in the bottom air gap 2 (figure below). The winding current is still 1 A as before, what is the flux density in air gap 1? (air gap 1 refers to the air gap with the cross-sectional area of Ac) B M = 00 i Area: Aci .B, =1.2 (T) g N H H = 940 (kA/m) S N BH curve of the magnet a. 0.66 (T) O b. 0.76 (T) Oc. 0.10 (T) O d. 0.4 (T) Oe. 0.025 (T) Of None of the rest O g. 0.05 (T) Oh. 0.5 (T)
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!