Three compounds all have the formula C5H8. All three compounds will decolorize bromine in CCl4. Compound 2 reacts with N

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Three compounds all have the formula C5H8. All three compounds
will decolorize bromine in CCl4. Compound 2 reacts with NaNH2,
while 1 and 3 do not. Compounds 1,2 and 3 both create pentane when
treated with H2 in the presence of a Pt catalyst. Under the same
conditions, compound 3 absorbs only 1 mol of H2 and gives a product
with the formula C5H10. Only compound 3 can go under ozonolysis and
gives OHC(CH2)3CHO. Compounds 1 and 2 are pairs of structural
isomers.
1. Draw the 3 compounds.
2. Draw the structure of terminal alkyne that can be reacted with
NaNH2.
3. Why compound 3 needs only 1 mole of H2/Pt?
4. Gives the structures of 1 and 2 that are pairs of structural
isomers.