- 1 Consider The Particle In A Ld Box Of Length L The Potential Inside The Box Is V X 0 And Outside The Box It Is V 1 (18.41 KiB) Viewed 199 times
1. Consider the particle in a ld box of length L. The potential inside the box is V(x) = 0 and outside the box, it is V=
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1. Consider the particle in a ld box of length L. The potential inside the box is V(x) = 0 and outside the box, it is V=
1. Consider the particle in a ld box of length L. The potential inside the box is V(x) = 0 and outside the box, it is V= . Use the variational method to solve for the Schrodinger equation for the system using the trial function Wapprox = N[x(x-L) + A[x(x-L)) + B(x(x-L)*1 a. Solve for the normalization factor N b. Express the energy E, in terms of the variational parameters A and B Solve for the value of the variational parameters A and B which will give the minimum E d. Calculate the minimum value of E (5 points) (5 points) (5 points) (5 points)