A proton initially has 7 = (10.0)+ (7.80)+ (1.40) and then 5.40 s later has (17.0)/+ (7.80)/+ (-15.0) (in M meters per s

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A Proton Initially Has 7 10 0 7 80 1 40 And Then 5 40 S Later Has 17 0 7 80 15 0 In M Meters Per S 1 (14.56 KiB) Viewed 273 times

A proton initially has 7 = (10.0)+ (7.80)+ (1.40) and then 5.40 s later has (17.0)/+ (7.80)/+ (-15.0) (in M meters per second). (a) For that 5.40 s, what is the proton's average acceleration awg in unit vector notation, (b) in magnitude, and (c) the angle between a and the positive direction of the x axis? ang (a) Number Units (b) Number Units (c) Number Units