This is a two part question. The change in enthalpy and entropy for a certain reaction are 2 kJ/mol and 12 J/K.mol, resp

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answerhappygod
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This is a two part question. The change in enthalpy and entropy for a certain reaction are 2 kJ/mol and 12 J/K.mol, resp

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This is a two part question.
The change in enthalpy and entropy for a certain reaction are 2 kJ/mol and 12 J/K.mol, respectively. The equilibrium constant Keg for this reaction is 1.89. Using the equations below, answer the following two questions.
the value kf univervsal gas is constant 8.315J,mol.k
A) Assuming standard conditions, calculate the free energy (AG°) for the reaction. You do not needto show your workings but don't forget your units.B) If the temperate was increased to 37 degC,would the reaction become more or less favorable.Justify your answer
A) Assuming standard conditions, calculate the free energy (AG°) for the reaction. You do not need
to show your workings but don't forget your units.
B) If the temperate was increased to 37 degC,would the reaction become more or less favorable.
Justify your answer
This Is A Two Part Question The Change In Enthalpy And Entropy For A Certain Reaction Are 2 Kj Mol And 12 J K Mol Resp 1
This Is A Two Part Question The Change In Enthalpy And Entropy For A Certain Reaction Are 2 Kj Mol And 12 J K Mol Resp 1 (51.37 KiB) Viewed 63 times
This is a two part question. The change in enthalpy and entropy for a certain reaction are 2 kJ/mol and 12 J/K.mol, respectively. The equilibrium constant Keq for this reaction is 1.89. Using the equations below, answer the following two questions. ᎪᏀᎾ . =AHⓇ - TASⓇ, AG-RT In Keq, ΔΗΘ Ase In Keq = RT R https://canvas.uts.edu.au/assessment questions/356938/files/1562667/download? verifier UVvzUkTwCFsZaxco9vbiBpuQSf3uYbNE5nvGotPC The value for the Universal gas constant is 8.315 J/mol.K. A) Assuming standard conditions, calculate the free energy (AG) for the reaction. You do not need to show your workings but don't forget your units. B) If the temperate was increased to 37 deg C, would the reaction become more or less favorable. Justify your answer +
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