For nos. I AND II: Given the following substitution reaction: CH3(CH₂)5Br + NaOH CH3(CH2)5OH + 1. What would be the effe

[answerhappygod]

For Nos I And Ii Given The Following Substitution Reaction Ch3 Ch 5br Naoh Ch3 Ch2 5oh 1 What Would Be The Effe 1 (131.96 KiB) Viewed 79 times

For nos. I AND II: Given the following substitution reaction: CH3(CH₂)5Br + NaOH CH3(CH2)5OH + 1. What would be the effect of changing the solvent from CH3OH to (CH3)₂S=O? The rate would increase because SN2 reactions favor a polar aprotic solvent. The rate would decrease because SN1 reactions favor a polar protic solvent. The potential change cannot be predicted. 'he rate will not change. II. What effect would be observed when changing the leaving group from the bromide ion to the iodide ion? The rate would increase because the iodide ion is a weaker base than the bromide ion. The rate would decrease because the bromide ion is a weaker base than the iodide ion. The potential change cannot be predicted. The rate will not change. In the synthesis of Rabeprazole, an antiulcerant, sodium hydroxide reacts via an SN2 reaction with the intermediate below: H₂CB- H₂ Which of the following carbon atoms would it most likely attack? Br Given the following synthesis: 1) BH 3 PBr3 I HN. || 2) H₂O₂, OHT If the product I was determined to be the of the Risomer, what would product II be? Br Br Br A. HN Br B. HN C. HN D. HN. Which of the following is the strongest nucleophile in polar protic solvents? O No answer text provided. O No answer text provided. O A) F- O B) CI- O C) HO- O D) CH3S- O E) CH30- 0 00