PS La Dung at po. HCI is a strong acid; thus, [HCI] -log[0.35] = 0.456 [H*] and pH = -log[H+] = Acetic acid is a weak ac

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Ps La Dung At Po Hci Is A Strong Acid Thus Hci Log 0 35 0 456 H And Ph Log H Acetic Acid Is A Weak Ac 1 (41.22 KiB) Viewed 49 times

PS La Dung at po. HCI is a strong acid; thus, [HCI] -log[0.35] = 0.456 [H*] and pH = -log[H+] = Acetic acid is a weak acid with K₂ = 1.74 x 10-5; thus, use ICE table to solve this problem: H₂O + CH₂COOHH₂O+ + CH₂COO CH₂COOH H+ CH₂COO Initial 0.35 M OM OM Change -X +x +x Equilibrium 0.35 x M x M x M [CH₂COO ][H,O+] 1² K₂ [CH₂COOH] [CH₂COOH] - X Assume [CH₂COO™] = [H₂O*] and [CH₂COOH] >>x; therefore: 1.74 x 10-5 0.35 x = 2.47 x 10³ = [H₂O+] pH = -log(2.47 x 10³) = 2.61 This answer verifies the initial assumption that [CH₂COOH] >>> x. (c) Here [CH3COOH] >> x cannot be assumed, so use ICE table approach with the quadratic equation to solve this problem: x² K₂ 0.035 - x Rearrange to 0=x² + K₂x -0.035 K = x² + (1.74 x 105)x (6.09 x 10-7) Solve using the quadratic equation: X = -(1.74 x 10-5) ± √(1.74 x 10-5)²-(4x −6.09 × 10-¹) 2 x = 7.717 x 104 = [H]; thus, pH = -log[7.717 × 10 +¹] = 3.11 4. (a) (b) pl