ACID BASE TITRATION (PART B)-REPORT SHEET CHEMISTRY 1108 SECTION PURPOSE: 0.20mL DATA: UNKNOWN NUMBER 18 Volume of aceti

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

ACID BASE TITRATION (PART B)-REPORT SHEET CHEMISTRY 1108 SECTION PURPOSE: 0.20mL DATA: UNKNOWN NUMBER 18 Volume of aceti

Post by answerhappygod »

Acid Base Titration Part B Report Sheet Chemistry 1108 Section Purpose 0 20ml Data Unknown Number 18 Volume Of Aceti 1
Acid Base Titration Part B Report Sheet Chemistry 1108 Section Purpose 0 20ml Data Unknown Number 18 Volume Of Aceti 1 (50.18 KiB) Viewed 53 times
Acid Base Titration Part B Report Sheet Chemistry 1108 Section Purpose 0 20ml Data Unknown Number 18 Volume Of Aceti 2
Acid Base Titration Part B Report Sheet Chemistry 1108 Section Purpose 0 20ml Data Unknown Number 18 Volume Of Aceti 2 (45.39 KiB) Viewed 53 times
ACID BASE TITRATION (PART B)-REPORT SHEET CHEMISTRY 1108 SECTION PURPOSE: 0.20mL DATA: UNKNOWN NUMBER 18 Volume of acetic acid used in every run 25.00mL Concentration of NaOH solution 0.3085M TITRATION DATA Run #1 Run #2 Final reading of burette (NaOH) 21.60mL 42.30ml Initial reading of burette (NaOH) 21.60 ml 42.30 ml Volume of NaOH used in Stration 20.70 mL 20-20 mL Endpoint Observations (relative colour and # of light pink light pink/ drops in final addition) Colour Purple colour (7dmps) (5 drops) 21.40 ML light pink NAME: Karla Shampon BENCH NO: 8A (3 chips) Run # 3 462.50ML Added mure NaOH (was at 325-ML) 450.00 ML +12.50 ml = 62.50M

RESULTS AND CALCULATIONS: other pairs of runs. Record all results to the correct number of significant figures, with the Show a detailed calculation for one pair of runs only below, show only the answers for the proper units. 1. Calculate the % difference between your runs. Answer 1&2 2 & 3 3 & 1 2. Balanced Equation Using only your best runs from above, perform the following calculation. As above, show a detailed calculation for only one run; just show the results for the other run(s). 3. Using the provided molarity of the NaOH solution, calculate the % acetic acid (by mass in each of your samples. Note: The total mass of each 25.00 mL sample is given by: Total Mass = density x volume. Assume the density of the acetic acid solution is 1.000 g/ml. 4. Calculate the average % acetic acid (your best runs only). Answer
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply