- 2 A Student Reacts 1 109 G Al With 50 Ml Of 4 M Naoh And An Excess Of H So4 In Solution To Produce 16 58 G Of Sodium Al 1 (29.09 KiB) Viewed 67 times
2. A student reacts 1.109 g Al with 50 mL of 4 M NaOH and an excess of H₂SO4 in solution to produce 16.58 g of sodium al
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2. A student reacts 1.109 g Al with 50 mL of 4 M NaOH and an excess of H₂SO4 in solution to produce 16.58 g of sodium al
2. A student reacts 1.109 g Al with 50 mL of 4 M NaOH and an excess of H₂SO4 in solution to produce 16.58 g of sodium alum. a. What will be the limiting reagent? b. Calculate the molar mass of sodium alum, NaAl(SO4)2 12H₂O. c. What is the theoretical yield of sodium alum? (The molar ratio between Al and sodium alum is 1 to 1.) d. What is the percent yield of sodium alum?
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