An enzyme catalyzed reaction exhibits simple Michaelis- Menten kinetics (Vo = (Vmax*S)/(Km+S)). The graph on the right s

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An Enzyme Catalyzed Reaction Exhibits Simple Michaelis Menten Kinetics Vo Vmax S Km S The Graph On The Right S 1 (37.29 KiB) Viewed 57 times

An enzyme catalyzed reaction exhibits simple Michaelis- Menten kinetics (Vo = (Vmax*S)/(Km+S)). The graph on the right shows a double reciprocal plot of substrate concentration (1/[S]) versus initial velocity (1/Vo) for the enzyme. The total enzyme concentration [ET] =2 μM. [In your answers make sure to include the appropriate units] 1. Calculate the Km value of the enzyme. 2.Calculate the turn-over number of the enzyme. 3 You repeat the experiment, but this time in the presence of a competitive inhibitor. The dissociation constant of the inhibitor (KI') is 4 x 10-9M and the inhibitor concentration is 8 x 10-9M. On the plot, graph the expected 1/S vs. 1/Vo behavior of the enzyme in the presence of the uncompetitive inhibitor. 4. In the presence of the inhibitor what is the apparent maximal velocity of the enzyme? 5. Which form of the enzyme does the inhibitor bind? [[ (E) or (ES) or (ES and E) ]] (circle your answer) wafe * 0.2 (10) -.2