- A Solution Is Prepared By Adding 0 080 Mole Of Ni Nh3 Cl To 0 50 L Of 2 2 Mnhs Calculate Ni Nh3 And N I 1 (20.12 KiB) Viewed 112 times
A solution is prepared by adding 0.080 mole of Ni(NH3). Cl, to 0.50 L of 2.2 MNHS Calculate NI (NH3), **) and [N??+) ) i
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A solution is prepared by adding 0.080 mole of Ni(NH3). Cl, to 0.50 L of 2.2 MNHS Calculate NI (NH3), **) and [N??+) ) i
A solution is prepared by adding 0.080 mole of Ni(NH3). Cl, to 0.50 L of 2.2 MNHS Calculate NI (NH3), **) and [N??+) ) in this solution. Koretall for Ni (NH3), 2+ is 5.5 x 10$ That is, (Ni (NHs)**) 5.5 x 10 N*]NH | for the overall reaction Ni+ (aq) + 6NH: (09) Ni (NH4). "* (aq) (Na (NH3), **] =D M 2 M
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