At a certain temperature, 0.330 mol CH₂ and 0.948 mol H₂S are placed in a 4.00 L container. CH₂(g) + 2 H₂S(g) = CS₂(g) +

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answerhappygod
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At a certain temperature, 0.330 mol CH₂ and 0.948 mol H₂S are placed in a 4.00 L container. CH₂(g) + 2 H₂S(g) = CS₂(g) +

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At A Certain Temperature 0 330 Mol Ch And 0 948 Mol H S Are Placed In A 4 00 L Container Ch G 2 H S G Cs G 1
At A Certain Temperature 0 330 Mol Ch And 0 948 Mol H S Are Placed In A 4 00 L Container Ch G 2 H S G Cs G 1 (18.08 KiB) Viewed 43 times
At a certain temperature, 0.330 mol CH₂ and 0.948 mol H₂S are placed in a 4.00 L container. CH₂(g) + 2 H₂S(g) = CS₂(g) + 4H₂(g) At equilibrium, 11.1 g CS, is present. Calculate K..
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