2.3 A bullet of mass 10 g, moving at a velocity of 300 m/s, strikes a wooden block of mass 1,99 kg resting on a flat hor

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2.3 A bullet of mass 10 g, moving at a velocity of 300 m/s, strikes a wooden block of mass 1,99 kg resting on a flat hor

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2 3 A Bullet Of Mass 10 G Moving At A Velocity Of 300 M S Strikes A Wooden Block Of Mass 1 99 Kg Resting On A Flat Hor 1
2 3 A Bullet Of Mass 10 G Moving At A Velocity Of 300 M S Strikes A Wooden Block Of Mass 1 99 Kg Resting On A Flat Hor 1 (22.82 KiB) Viewed 56 times
2.3 A bullet of mass 10 g, moving at a velocity of 300 m/s, strikes a wooden block of mass 1,99 kg resting on a flat horizontal surface as shown in the diagram below. The bullet becomes embedded in the block. Ignore the effects of air friction. BEFORE COLLISION AFTER COLLISION v=300 m-s¹¹ 1,99 kg m=10g wooden block block-bullet system 2.3.1 Write down in words the principle of conservation of linear momentum. (2) 2.3.2 Calculate the speed of the block-bullet system immediately after the collision. (4)
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