A wire with mass 45.0 g is stretched so that its ends are tied down at points a distance 76.0 cm apart. The wire vibrate

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A wire with mass 45.0 g is stretched so that its ends are tied down at points a distance 76.0 cm apart. The wire vibrate

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A Wire With Mass 45 0 G Is Stretched So That Its Ends Are Tied Down At Points A Distance 76 0 Cm Apart The Wire Vibrate 1
A Wire With Mass 45 0 G Is Stretched So That Its Ends Are Tied Down At Points A Distance 76 0 Cm Apart The Wire Vibrate 1 (55.31 KiB) Viewed 33 times
A Wire With Mass 45 0 G Is Stretched So That Its Ends Are Tied Down At Points A Distance 76 0 Cm Apart The Wire Vibrate 2
A Wire With Mass 45 0 G Is Stretched So That Its Ends Are Tied Down At Points A Distance 76 0 Cm Apart The Wire Vibrate 2 (89.31 KiB) Viewed 33 times
A wire with mass 45.0 g is stretched so that its ends are tied down at points a distance 76.0 cm apart. The wire vibrates in its fundamental mode with frequency 60.0 Hz and with an amplitude at the antinodes of 0.330 cm. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of A giant bass viol. ▼ Part A What is the speed of propagation of transverse waves in the wire? Express your answer in meters per second. 15. ΑΣΦ ? Submit Previous Answers Request Answer X Incorrect; Try Again; 8 attempts remaining Part B Compute the tension in the wire. Express your answer in newtons. VE ΑΣΦΑ ? Y C 11 m/s

▼ Part C Find the magnitude of the maximum transverse velocity of particles in the wire. Express your answer in meters per second. IVE ΑΣΦ PAD ? Umax = Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining Part D Find the magnitude of the maximum acceleration of particles in the wire. Express your answer in meters per second squared. m/s
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