Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is

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Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is

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Coulomb S Law For The Magnitude Of The Force F Between Two Particles With Charges Q And Q Separated By A Distance D Is 1
Coulomb S Law For The Magnitude Of The Force F Between Two Particles With Charges Q And Q Separated By A Distance D Is 1 (141.04 KiB) Viewed 31 times
Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is |F| = K |QQ| d² 1 where K = and Απερ €0 = 8.854 × 10-¹2 C²/(N. m²) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q₁ = -11.0 nC, is located at x₁ = -1.725 m; the second charge, q2 = 35.5 nC, is at the origin (x = 0). Part A What is (Fnet 3) x, the x-component of the net force exerted by these two charges on a third charge q3 = 54.0 nC placed between 91 and 92 at 3 = -1.050 m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures. ► View Available Hint(s) V ΑΣΦ (Fnet 3) x 5 - 1.08 107 = Submit Previous Answers ? N
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