Part D dD = 225 mm tD = 5.5 mm

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answerhappygod
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Part D dD = 225 mm tD = 5.5 mm

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Part D
dD = 225 mm
tD = 5.5 mm
Part D Dd 225 Mm Td 5 5 Mm 1
Part D Dd 225 Mm Td 5 5 Mm 1 (83.59 KiB) Viewed 32 times
Part D - There are 3 questions in this part Consider a circular hollow section, with outer diameter dp (in mm), and thickness tp (in mm). The circular hollow section is made from aluminium which has a density of 2700 kg/m³ and a shear modulus G = 30000 MPa. Question 11 2 pts Question D1 What twisting moment (in kNm) will cause a maximum shear stress of 105 MPa? Give your answer as a positive number.

Question 12 2 pts Question D2 The CHS is changed so that the thickness is now 1.5tp but the diameter do is unchanged. The material is changed to steel which has a density of 7850 kg/m³ and a shear modulus G = 70000 MPa. What twisting moment (in kNm) will cause a maximum shear stress of 105 MPa? Give your answer as a positive number. Question 13 2 pts Question D3 The new CHS (ie the one made from steel with the larger thickness), is now filled with concrete which has density 2450 kg/m³. What is the mass per unit length of the concrete filled CHS (in kg/m)? If you need to use gravity, please use g= 10 m/s².
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