For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending mom

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For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending mom

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For The Simply Supported Beam Subjected To The Loading Shown Derive Equations For The Shear Force V And The Bending Mom 1
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For The Simply Supported Beam Subjected To The Loading Shown Derive Equations For The Shear Force V And The Bending Mom 2
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For The Simply Supported Beam Subjected To The Loading Shown Derive Equations For The Shear Force V And The Bending Mom 4
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For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a-2.75 m, b-4.50 m, Pe=40kN, and Pc-70kN. Construct the shear- force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. Pc B a Calculate the reaction forces A, and D, acting on the beam, Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since A, O, it has been omitted from the free-body diagram.) Pc D b

Part 2 Determine the shear force acting at each of the following locations: (a)x=2m (b)x=4m (c) x 8m Note that x-0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. Answers: (a) V- (b) V- (c) V- 3 3 3 KN

+ Part 3 Determine the bending moment acting at each of the following locations: (a)x= 2m (b)x=2.75 m (i.e., at point B) (c)x=4m (d) x 5.50 m (i.e., at point C) (e) x=8m Note that x-0 at support A. When entering your answers, use the bending-moment sign convention detailed in Section 7.2. Answers: (a) M= i kN-m (b) M- i kN-m (c) M= i kN-m (d) M- i kN-m (e) M- KN-m

Part 4 Use your bending-moment diagram to determine the maximum bending moment, Mmax and its location, Xmax Use the bending- moment sign convention detailed in Section 7.2. Answers: Xmax m kN-m Mmax i
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