mw.taibahu.edu.sa/webapps/assessment/take/launch.jsp?course assessment id= 143765 1&course id 1380004_1&content id 14308

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mw.taibahu.edu.sa/webapps/assessment/take/launch.jsp?course assessment id= 143765 1&course id 1380004_1&content id 14308

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Mw Taibahu Edu Sa Webapps Assessment Take Launch Jsp Course Assessment Id 143765 1 Course Id 1380004 1 Content Id 14308 1
Mw Taibahu Edu Sa Webapps Assessment Take Launch Jsp Course Assessment Id 143765 1 Course Id 1380004 1 Content Id 14308 1 (67.64 KiB) Viewed 58 times
mw.taibahu.edu.sa/webapps/assessment/take/launch.jsp?course assessment id= 143765 1&course id 1380004_1&content id 14308182 18stepenull. t Moving to another question will save this response Question 1 of 4 Question 1 10 points Save Answer An equal-tangent vertical curve is to be constructed between grades of -3.0% (initial) and +1.0% (final). The PVI is at station 11+000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway of the point M at the station 11+200 must be at 424.5 m. We need to design the curve. For that: 2) 1) Write the position of the point M called xM as a function of the length L of the curve. Starting from the parabolic equation of the coordinates (XM,YM) of the point M, calculate the value of the curve length L. 3) Calculate the values of the stations in PVC and in PVT. Attach File Browse My Computer Question 1 of 4 Moving to another question will save this response & ENG 10:01 PM
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