Consider an inclined bar made of two sections of length L₁ connected to a spring of constant k₁ and length L₂ connected

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

Consider an inclined bar made of two sections of length L₁ connected to a spring of constant k₁ and length L₂ connected

Post by answerhappygod »

Consider An Inclined Bar Made Of Two Sections Of Length L Connected To A Spring Of Constant K And Length L Connected 1
Consider An Inclined Bar Made Of Two Sections Of Length L Connected To A Spring Of Constant K And Length L Connected 1 (92.15 KiB) Viewed 53 times
Consider an inclined bar made of two sections of length L₁ connected to a spring of constant k₁ and length L₂ connected to a damper of constant c such that the co-linear sections is initially at a rotation of fo to the horizontal that is connected to a pivot and then allowed to rotate by a small clockwise angle as shown below. C1 L2 k₁ L₁ 00 L3 k3 L5 L4 Attached perpendicular to the intersection of sections L₁ and L₂ is another section of length L3 to which is attached at its end point a rectangular planar mass of mass m with a breadth of b and a width of w. When the mechanism rotates by a clockwise angle a wire rope connected to the center-of-mass of the planar rectangle pulls a spring of spring constant k3. Considering the above system, determine the following information: 1.1 The equation of motion of the rotating rod in the form med + Ce+kein (15) terms of the available information using kinematics and Newtons equations; 1.2 The natural angular frequency w, and damping factor of the rotating rod if (3) 0 + 25w₁0+w²0= 0 by manipulating the equation of motion if L₁ = 0.400 m. L2 = 0.550 m, L3= 0.720 m, L₁= 0.630 m, Ls = 0.420 m, k₁= 800 N/m, k3= 2450 N/m, c₁ = 450 Ns/m, b = 0.065 m, w = 0.037 m, and 0o = 22° respectively. Total Marks: [18] 3 MOM3602 6 June 2022 Supplied Applicable Formulae for Question 1 I₁ = 1/2m(b² + Iy +w²) I|| = Icom +md² 1 më+ci+kr = 0 + #+25w₁t+w²x = 0,w₂₁ m 6 W B k с .S = m 2mWn << 1 ⇒ r = C[exp(-Cwt)] [sin (wat +)], w₁ = w₁ √/1-(² v=[Cw₁ cos(wat +)-(Cw, sin(wat + x)] e-swit
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply