- 3 25 Pts The Position Of A Marble Sliding Down A Ramp Is Given By The Following Coordinates X 4t M Y 2t M 1 (22.57 KiB) Viewed 32 times
3. [25 pts] The position of a marble sliding down a ramp is given by the following coordinates: x= (4t³) [m], y=2t² [m],
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3. [25 pts] The position of a marble sliding down a ramp is given by the following coordinates: x= (4t³) [m], y=2t² [m],
3. [25 pts] The position of a marble sliding down a ramp is given by the following coordinates: x= (4t³) [m], y=2t² [m], z=(5-t5/2) [m], where t is in seconds. At t = 5 secs, calculate the (a) position vector, (b) velocity vector, and (c) the acceleration vectors, all in cartesian vector form. Then, calculate the magnitude of the ball's (d) displacement, (e) velocity and (f) acceleration. Do not forget the proper units and vector notation.