2-19 E = 70 G Pa $20 A ATT = 70х09 Ра P-4 KN &6000 Q? if deflection at I A is zero deflection of B sul PLAB 4x10 x 0.4 б

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1 (71.77 KiB) Viewed 42 times

2 (71.86 KiB) Viewed 42 times

3 (70.63 KiB) Viewed 42 times

4 (76.02 KiB) Viewed 42 times

2-19 E = 70 G Pa $20 A ATT = 70х09 Ра P-4 KN &6000 Q? if deflection at I A is zero deflection of B sul PLAB 4x10 x 0.4 бав е рав F 70x10¹xAAB PAB - Id² = = (0.02) ² FF Spc = (P-9) LBC, L=0.5 BC E ABC C.T = से 104m 10.5m

бвс = бав from Е4050 determine Ф гов - бас = бав = 3 Е = 70 бра Al E = 105 GPa B хотир P = 450 In б-бы - б С AL Br P= PA₁ + Br б= PL AE бвг Br Е.б L w 11 со PBr I Авт - S 8 => P : AL L Рог - бар, Евг = 2 AL (0) 90 AL 1/ - С PAL AAL AL Br -60mm

P = SAE + SALE EAL Br L P = (1) (AR. For + Ane EAL) => E Br σ = EE Br = Er E v Br 0 = EE I ✓ E&S are the same. Ve O'Br Mainport 2-41 E 200 GP E = 1056₁ ds=40mm db = 30mm for Brass & Aluminum. steel D B> (180/180/10/2 160 Bras

(ED) P₁ = 0 (DC) P₂-40KN (CB) 'BA) No support in E 970 боки = 40 KN L3 L4 A/= A2 PA₁ = 60+40KN = 100KN 1₂ = A4 √₁ = [Pihi = P41 +₂4+ P3L3 P4 L4 AE AE A, Eb A₂ E₂ A₂ Es А, Ев + Second Scenario A C E 2₂ - R -RELI -RE² 1 SR = Σ Pili Ai E + A₁ Eb A ES б= бы ты =0 substah due to determine EC-P-R CA = P₁ C 08 300 - E 40 KN KRE RE