- Oa Constant 10 Rad S F 500n M2 1 M3 2 M4 2 M5 1 M6 1 Kg Point B Is Fixed And The Center Of Mass Of Limk 5 1 (53.64 KiB) Viewed 43 times
OA constant 10 rad/s F=500N m2 = 1, m3 = 2, m4 = 2, m5 = 1, m6 = 1 kg Point B is fixed and the center of mass of limk 5 ● Find M moment and drav graph at matlab (horizontal axis 02 (degrees), vertical axis in Nm) Find the equations of motion of the limbs and compare with option 1. ● Draw the horizontal and vertical components of the forces from the fixed link and the 3 link on the OA link. 1. draw the components in the link direction and perpendicular to the link ● What should be the cross-sectional dimensions so that this link can withstand the loads it is exposed to twice as safely? (Think of the cross section of the link as a hollow square profile with a thickness of 't', the material is St 37 steel) USE MATLAB FOR ALL
OB=L₁=70 cm, OA-L₂-30 cm, AC-L3=150 cm, CD-=L4-100 cm, e-20cm -Oº. M 0₂ F