1. In Fig. 3. If VBE(SAT) = 0.75 V, VBE(FA) = 0.65 V, VD(ON) = 0.65 V, VCE(SAT) = 0.1 V. When VIN is high, the current p

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answerhappygod
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1. In Fig. 3. If VBE(SAT) = 0.75 V, VBE(FA) = 0.65 V, VD(ON) = 0.65 V, VCE(SAT) = 0.1 V. When VIN is high, the current p

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1 In Fig 3 If Vbe Sat 0 75 V Vbe Fa 0 65 V Vd On 0 65 V Vce Sat 0 1 V When Vin Is High The Current P 1
1 In Fig 3 If Vbe Sat 0 75 V Vbe Fa 0 65 V Vd On 0 65 V Vce Sat 0 1 V When Vin Is High The Current P 1 (52.37 KiB) Viewed 38 times
1. In Fig. 3. If VBE(SAT) = 0.75 V, VBE(FA) = 0.65 V, VD(ON) = 0.65 V, VCE(SAT) = 0.1 V. When VIN is high, the current pass-through RD is A. 0.13 MA B. 0.15 mA C. 0 D. 0.02 MA 2. In Fig. 3. If Vcc=5 V, VBE(SAT) = 0.75 V, VBE(FA) = 0.65 V, VD(ON) = 0.65 V, VCE(SAT) = 0.1 V. When VIN is low, the value of the current Icc is A. 0 A Vo B. 2.43 MA ifice C. 2.125 mA D. 1.33 MA PR, 1.75 k 3. In Fig. 3. When VIN is low, the value of the current IRC is A. 1.33 mA B. 0.817 mA C. OA D. 2.125 mA 4. In Fig. 3. When VIN is high, the value of the current IRC is A. 1.33 MA B. 0.817 mA. C. O A D. 2.125 mA (1-p)R, 2 k VOK D₁ Qu D₂ ▷ Fig. 3 RD IRC Re6 km2 5 km2 H. Qa - VOUT
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