A 3-phase, 4-wire system which has a system voltage of 254-V L-N with loads connected in wye; Za = 10/0° ohm; Zb= 10/37°

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A 3 Phase 4 Wire System Which Has A System Voltage Of 254 V L N With Loads Connected In Wye Za 10 0 Ohm Zb 10 37 1 (178.13 KiB) Viewed 25 times

A 3-phase, 4-wire system which has a system voltage of 254-V L-N with loads connected in wye; Za = 10/0° ohm; Zb= 10/37° ohm and Zc = 102-53° ohm. Calculate the power dissipated on each load and the neutral current when phase sequence is a) abc and b) acb You can use the sample problem below as guide answering the problem, please use 3 decimal points for the final answer! Sample Problem solution for guide (the given from this problem is different from the problem above) Solution. (i) Phase sequence RYB (Fig. 19.80) 254 0: VYN RN 254 120; Vav 254 120 VRN 254 0 IR IRN 25.4 0. RR 10 0 2542-120° .=25.42-157= 25.4(–0.9205 – j0.3907)=–2338– 19.95 YN 10237° -IN VAN ly (a) Fig. 19.80 2542120° AN = 25.42173°= 25.4(-0.9925+ 0.1219)=-252+j31 102-53° (1+1+1)--[25.4+(-23.38-9.55) + (−25.21 +£3.1)] = 23.49 +j6.85 24.46/16°15' Now R = 102; R₂ = 10 cos 37°= 82; R₂ = 10 cos 53° = 652 25.4² 8 5,162 W 25.4² 10 6.452 W: Wy W₂ 25.4² 6 3,871 W (ii) Phase sequence RBY [Fig. 19.81] 254 0:VYN 254 120 R.N BN 254 120 254 0 10 0 25.4 0 120° 254 120 120° 25.4 83 10 37 - (3.1 +25.2) 120 254 120 10 53 IN 25.4 67 (9.95 j23.4) (Ig Iy 1₂) (38.45 1.8) --38.45-1.8-3852-177.3°. 254 V VIN Fig. 19.81