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£⑧=（-¢2-③（-4×2-2¢+4)：（=1,-8
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£⑧=（-¢2-③（-4×2-2¢+4)：（=1,-8
£⑧=（-¢2-③（-4×2-2¢+4)：（=1,-8
Find the equation of the tangent line to the graph of f(x) at the (x, y)-coordinate indicated below. f(x)= (-x²-3)(-4x²-2x+4):(-1.-8) Answer 2 Points y = 1.doc V S #3 80 13 LU E D Chap020.doc a FA S4 $ R 20 85 % FL af T MacBook Air A 6 Chap013 rev (1) doc G Y 49 & 7 8 67 H stv .00 Chap013 edoc D : Dil 19 8 9 0 U 100 0 J K M v! L < ►
Find the equation of the tangent line to the graph of f(x) at the (x, y)-coordinate indicated below. f(x)= (-x²-3)(-4x²-2x+4):(-1.-8) Answer 2 Points y = 1.doc V S #3 80 13 LU E D Chap020.doc a FA S4 $ R 20 85 % FL af T MacBook Air A 6 Chap013 rev (1) doc G Y 49 & 7 8 67 H stv .00 Chap013 edoc D : Dil 19 8 9 0 U 100 0 J K M v! L < ►