En una titulación de 50.00 mL de 0.0500M HC2H3O2 (acido acético(Ka = 1.75 x 10-5),) con 0.100 M NaOH añadimos 1.00mL d

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answerhappygod
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En una titulación de 50.00 mL de 0.0500M HC2H3O2 (acido acético(Ka = 1.75 x 10-5),) con 0.100 M NaOH añadimos 1.00mL d

Post by answerhappygod »

En una titulación de 50.00 mL de 0.0500M
HC2H3O2 (acido
acético(Ka = 1.75 x 10-5),) con 0.100 M
NaOH añadimos 1.00mL de NaOH teniendo en cuenta la concentración de
C2H3O2- y la de
HC2H3O2 el pH de
esta segunda etapa es:
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