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Vo(t) = −RC dv in (1) dt
CHI Vin CH1 gnd R₁ 2.2 ΚΩ C₁ HI 4.7 nF + 22 ΚΩ RF1 741 Vout CH2 CH2 gnd I
Vo(t) = −RC dv in (1) dt CHI Vin CH1 gnd R₁ 2.2 ΚΩ C₁ HI 4.7 nF + 22 ΚΩ RF1 741 Vout CH2 CH2 gnd I
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answerhappygod
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Vo(t) = −RC dv in (1) dt CHI Vin CH1 gnd R₁ 2.2 ΚΩ C₁ HI 4.7 nF + 22 ΚΩ RF1 741 Vout CH2 CH2 gnd I
By using this formula please calculate the output voltage of the op-Amp differentiator
Vin =1V
Vo(t) = −RC dv in (1) dt
CHI Vin CH1 gnd R₁ 2.2 ΚΩ C₁ HI 4.7 nF + 22 ΚΩ RF1 741 Vout CH2 CH2 gnd I
Vin =1V
Vo(t) = −RC dv in (1) dt
CHI Vin CH1 gnd R₁ 2.2 ΚΩ C₁ HI 4.7 nF + 22 ΚΩ RF1 741 Vout CH2 CH2 gnd I
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