-qh2o reaction -h for the reaction -h per mole

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answerhappygod
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-qh2o reaction -h for the reaction -h per mole

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-qh2o reaction
-h for the reaction
-h per mole
Qh2o Reaction H For The Reaction H Per Mole 1
Qh2o Reaction H For The Reaction H Per Mole 1 (46.61 KiB) Viewed 54 times
Qh2o Reaction H For The Reaction H Per Mole 2
Qh2o Reaction H For The Reaction H Per Mole 2 (22.93 KiB) Viewed 54 times
Qh2o Reaction H For The Reaction H Per Mole 3
Qh2o Reaction H For The Reaction H Per Mole 3 (32.82 KiB) Viewed 54 times
Heat of Neutralization 22.0c Original temp of HCl solution Original temp of NaOH solution 22.60 Final temp of neutralized mixture 35.30 Change in temp (use average original temp of 26.6C HCl and NaOH) QH20 for the reaction (get mass using 50.0 U ml solution and d=1.02 g/mL) AH for the reaction (egn 4) J AH per mole kJ/mol

Preaction = AH reaction = -9H20 (eqn 4) NaOH(s) - Na*(aq) + OH(aq); AH = AH solution (eqn 5) Solution with o int H'(am + OH(aq) - HO (O); AH = Anetration (en 6)

-27X-Blackboard-Expiration=1638176400000&X-Blackboard-Signature=WZUHUMegvo%2B0F 100% orua Suosiance q = Csxm X At (en 1) 4720 = -metal (eqn 2) now express heat flow in terms of Equation 1 for both the water and the metal, we get (Equation 3): q=CH20 X M20 X Atuzo = - metal X metal * Atmetar (eqn 3) 39F
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