A solution of Ca(OH)2 (FM =74.09) was used in determining the equivalent weight of an unknown acid. To do so, the said solution was standardized against 0.1235 g KHP (FM = 204.22), requiring 7.45 mL to reach the phenolphthalein end point. On the other hand, a 0.0543 g unknown acid requires 12.85 mL standard Ca(OH)2 to reach desired endpoint.
a. Calculate the standard normality of Ca(OH)2
b. Calculate the equivalent weight of the unknown acid.
c. From the table, what is the most probable identity of the unknown acid?
- Please Solve With Clear Correct And Detailed Solutions For An Upvote A Solution Of Ca Oh 2 Fm 74 09 Was Used In Det 1 (33.71 KiB) Viewed 63 times
Probable identity Ascorbic Acid, C6H806 Malonic Acid, C3H404 Succinic Acid, C4H604 Citric Acid, C6H807 Formula weight 176.124 104.062 118.088 192.124 Proticity 1 2 2 3