Question 1 A standing inspector picks up 20 lb castings from a pallet the floor and lift it 50 inches high with a horizo

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Question 1 A standing inspector picks up 20 lb castings from a pallet the floor and lift it 50 inches high with a horizo

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Question 1 A Standing Inspector Picks Up 20 Lb Castings From A Pallet The Floor And Lift It 50 Inches High With A Horizo 1
Question 1 A Standing Inspector Picks Up 20 Lb Castings From A Pallet The Floor And Lift It 50 Inches High With A Horizo 1 (33.56 KiB) Viewed 50 times
Question 1 A Standing Inspector Picks Up 20 Lb Castings From A Pallet The Floor And Lift It 50 Inches High With A Horizo 2
Question 1 A Standing Inspector Picks Up 20 Lb Castings From A Pallet The Floor And Lift It 50 Inches High With A Horizo 2 (23.78 KiB) Viewed 50 times
Question 1 A Standing Inspector Picks Up 20 Lb Castings From A Pallet The Floor And Lift It 50 Inches High With A Horizo 3
Question 1 A Standing Inspector Picks Up 20 Lb Castings From A Pallet The Floor And Lift It 50 Inches High With A Horizo 3 (38.67 KiB) Viewed 50 times
Question 1 A standing inspector picks up 20 lb castings from a pallet the floor and lift it 50 inches high with a horizontal distance of 20 inches for first visual inspection. He then puts the casting on a work area 25 inches from the floor and closer to the body (a minimum horizontal distance) for second inspection. Assume a frequency of 1 lift per minute over 8 hours (multiplier=0.75) and a poor coupling multiplier (0.90). This led to the following calculations RWL-51 (10/20) (1-0075/50-30) (x2+1.8/50) (1-0032(0)) (0.75) (0.90) 12.52 RWL $1 (10/10) (1-0075/25-30) (82 +1.8/25) (1-0032(0)) (0.75) (0,90)- 29.56 LI-20/12.031.66 LI-20/29.56-0.68 1.1 Which lift is acceptable according to the NIOSH guidelines? (2) 1.2 You were requested to investigate the above situation and recommend changes to the layout to get the LI value below a value of 1 (company policy). Shortly discuss what changes you will make and then show the calculated results of your suggested changes proving that I will be below 1 using formulas provided. (10) RWL = 51 (10/H) (1-.0075 V-301) (-82+1.8/D) (1 - 0032A) (FM) (CM) LI= load weight/RWL RWL 51 (10/H) (1.0075 V-301) (.82 + 1.8/D) (1 - 0032A) (FM) (CM) LI= load weight/RWL [11]
Question 2 In Tsabalala Heavy Engineering shop an all-day study revealed the following noise sources: 0.25 hrs., 100 dBA; 1 hr., less than 80 dBA; 4 hrs., 90 dBA; 3 hrs., 97 dBA. 2.1 What is the dose exposure? (5) 2.2 Is this company in compliance? (2) 2.3 What is the TWA noise level? (2) D = 100 X (C/T, + C/T₂+...+C/T₂) ≤ 100 TWA 16.61 X log (D/100) + 90 Permissible Noise Exposure Table Duration per day (hr) Sound level (dBA) 8 90 6 92 4 95 3 97 100 102 105 110 115 2 1.5 1 0.5 0.25 or less [9]
Question 3 A new method is being evaluated. It is estimated to save R35 000 in the first year, have a loss of R7 000 the second year, save R56 000 the third year and R21 000 the fourth year. If the company expects a 20% return on investment, how much capital can be invested in this method? (5) P = F(1 + i)-n [5] Question 4 The following data is supplied for Tshabalala's Confectionery. Element A is "pick raw materials" Element B is "measure materials" Element C is "mix materials" Element D is "pan materials" Element E is "place panned materials" These elements are timed in groups as follows: A+B+C = Element 1 = 6.25min B+C+D=Element 2 = 9.75min C+D+E=Element 3 = 20.75min D+E+A=Element 4 = 22.5min E+A+B=Element 5= 21min Compute the standard data values for elements A, B, C, D, and E. Page 1 of 5 [15]
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