29,32
use separation of variables to find the solution to the differential equation subject to the initial condition.
thx
dz di dw do dw dy du 32. x(x + 1) = dx 30. = 2 + 21², z = 5 when t = 0 = 0w² sin 0², w(0) = 1 -w² tany, w(0) = 2 =ư, u(1)=1
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