The sketch following shows the traverse from A to B, along the horizontal alignment of a rural highway. A circular curve

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The Sketch Following Shows The Traverse From A To B Along The Horizontal Alignment Of A Rural Highway A Circular Curve 1 (82.11 KiB) Viewed 28 times

The sketch following shows the traverse from A to B, along the horizontal alignment of a rural highway. A circular curve joins the points BC and EC. The Y and X coordinates of points A, PI and B are given in the table below. Assume point A is situated at chainage 0+000. PI A EC BC A B BC = Beginning of the circular curve EC End of the circular curve. A = Central angle Sketch not to scale Point Y (m) X (m) Radius (m) A -16155.234 +25271.315 0 PI -18572.006 +24003.839 300 T B -23132.364 +26215.211 0 2.1 Do join calculations and determine the central angle (A). 2.2 Calculate the circular curve length (L) and the tangent length (T). 2.3 Compute the chainages of BC, EC, and the mid-point on the curve (MP). 2.4 Do polar calculations and determine the coordinates of BC. L = Formula TRA 180 Rtan (2) = (22) (4) (6) (8) [40 marks]